What is the value of sin(tan^(-1)(x))?

Practice Questions

Q1
What is the value of sin(tan^(-1)(x))?
  1. x/√(1+x^2)
  2. √(1+x^2)/x
  3. 1/x
  4. x

Questions & Step-by-Step Solutions

What is the value of sin(tan^(-1)(x))?
  • Step 1: Understand that tan^(-1)(x) is the angle whose tangent is x. Let's call this angle θ. So, θ = tan^(-1)(x).
  • Step 2: By the definition of tangent, we have tan(θ) = x. This means that in a right triangle, the opposite side is x and the adjacent side is 1.
  • Step 3: Use the Pythagorean theorem to find the hypotenuse of the triangle. The hypotenuse h can be calculated as h = √(opposite^2 + adjacent^2) = √(x^2 + 1^2) = √(x^2 + 1).
  • Step 4: Now, we need to find sin(θ). The sine of an angle in a right triangle is the ratio of the length of the opposite side to the length of the hypotenuse. So, sin(θ) = opposite/hypotenuse = x/√(x^2 + 1).
  • Step 5: Therefore, we can conclude that sin(tan^(-1)(x)) = x/√(1 + x^2).
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