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Find the determinant of the matrix \( D = \begin{pmatrix} 1 & 0 & 2 \\ 0
Find the determinant of the matrix \( D = \begin{pmatrix} 1 & 0 & 2 \\ 0 & 1 & 3 \\ 0 & 0 & 1 \end{pmatrix} \).
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Find the determinant of the matrix \( D = \begin{pmatrix} 1 & 0 & 2 \\ 0 & 1 & 3 \\ 0 & 0 & 1 \end{pmatrix} \).
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The determinant of an upper triangular matrix is the product of its diagonal elements, which is 1.
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Q: Find the determinant of the matrix \( D = \begin{pmatrix} 1 & 0 & 2 \\ 0 & 1 & 3 \\ 0 & 0 & 1 \end{pmatrix} \).
Solution:
The determinant of an upper triangular matrix is the product of its diagonal elements, which is 1.
Steps: 5
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Step 1: Identify the matrix D, which is given as D = [[1, 0, 2], [0, 1, 3], [0, 0, 1]].
Step 2: Recognize that D is an upper triangular matrix. This means all the elements below the main diagonal are zero.
Step 3: Find the diagonal elements of the matrix D. The diagonal elements are 1 (first row), 1 (second row), and 1 (third row).
Step 4: Calculate the product of the diagonal elements. Multiply 1 * 1 * 1.
Step 5: The result of the multiplication is 1, which is the determinant of the matrix D.
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