A solution has a density of 1.2 g/mL and contains 30 g of solute. What is the molarity if the molar mass of the solute is 60 g/mol?
Practice Questions
1 question
Q1
A solution has a density of 1.2 g/mL and contains 30 g of solute. What is the molarity if the molar mass of the solute is 60 g/mol?
0.5 M
1 M
2 M
1.5 M
Volume of solution = mass / density = 30 g / 1.2 g/mL = 25 mL = 0.025 L. Moles of solute = 30 g / 60 g/mol = 0.5 moles. Molarity = 0.5 moles / 0.025 L = 20 M.
Questions & Step-by-step Solutions
1 item
Q
Q: A solution has a density of 1.2 g/mL and contains 30 g of solute. What is the molarity if the molar mass of the solute is 60 g/mol?
Solution: Volume of solution = mass / density = 30 g / 1.2 g/mL = 25 mL = 0.025 L. Moles of solute = 30 g / 60 g/mol = 0.5 moles. Molarity = 0.5 moles / 0.025 L = 20 M.
Steps: 8
Step 1: Identify the given information. We have a density of 1.2 g/mL, a mass of solute which is 30 g, and a molar mass of the solute which is 60 g/mol.
Step 2: Calculate the volume of the solution using the formula: Volume = mass / density. Here, we use 30 g (mass) divided by 1.2 g/mL (density).
Step 3: Perform the calculation: 30 g / 1.2 g/mL = 25 mL.
Step 4: Convert the volume from mL to L because molarity is expressed in moles per liter. 25 mL is equal to 0.025 L (since 1000 mL = 1 L).
Step 5: Calculate the number of moles of solute using the formula: Moles = mass / molar mass. Here, we use 30 g (mass) divided by 60 g/mol (molar mass).
Step 6: Perform the calculation: 30 g / 60 g/mol = 0.5 moles.
Step 7: Finally, calculate the molarity using the formula: Molarity = moles of solute / volume of solution in L. Here, we use 0.5 moles divided by 0.025 L.
Step 8: Perform the calculation: 0.5 moles / 0.025 L = 20 M.
