What is the vapor pressure of a solution containing 1 mole of a non-volatile sol

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Question: What is the vapor pressure of a solution containing 1 mole of a non-volatile solute in 10 moles of solvent, assuming ideal behavior?

Options:

Correct Answer: 0.9 P0

Solution:

Using Raoult\'s law, the vapor pressure of the solution = (moles of solvent / total moles) * P0 = (10 / 11) * P0 = 0.909 P0.

What is the vapor pressure of a solution containing 1 mole of a non-volatile solute in 10 moles of solvent, assuming ideal behavior?

What is the vapor pressure of a solution containing 1 mole of a non-volatile solute in 10 moles of solvent, assuming ideal behavior?

Step 1: Identify the number of moles of solute and solvent. Here, we have 1 mole of solute and 10 moles of solvent.
Step 2: Calculate the total number of moles in the solution. Total moles = moles of solute + moles of solvent = 1 + 10 = 11 moles.
Step 3: Use Raoult's law to find the vapor pressure of the solution. Raoult's law states that the vapor pressure of the solution is equal to the mole fraction of the solvent multiplied by the vapor pressure of the pure solvent (P0).
Step 4: Calculate the mole fraction of the solvent. Mole fraction of solvent = moles of solvent / total moles = 10 / 11.
Step 5: Multiply the mole fraction of the solvent by the vapor pressure of the pure solvent (P0) to find the vapor pressure of the solution. Vapor pressure of the solution = (10 / 11) * P0.
Step 6: Simplify the expression to get the final answer. Vapor pressure of the solution = 0.909 P0.

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