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If 0.1 M of a weak acid has a pH of 4.0, what is the Ka of the acid?
If 0.1 M of a weak acid has a pH of 4.0, what is the Ka of the acid?
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Practice Questions
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Q1
If 0.1 M of a weak acid has a pH of 4.0, what is the Ka of the acid?
1 x 10^-4
1 x 10^-5
1 x 10^-6
1 x 10^-7
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Using the formula Ka = [H+]^2 / [HA], where [H+] = 10^(-4) M and [HA] = 0.1 M, we find Ka = (10^-4)^2 / 0.1 = 1 x 10^-5.
Questions & Step-by-step Solutions
1 item
Q
Q: If 0.1 M of a weak acid has a pH of 4.0, what is the Ka of the acid?
Solution:
Using the formula Ka = [H+]^2 / [HA], where [H+] = 10^(-4) M and [HA] = 0.1 M, we find Ka = (10^-4)^2 / 0.1 = 1 x 10^-5.
Steps: 8
Show Steps
Step 1: Understand that pH is a measure of the concentration of hydrogen ions (H+) in a solution. The formula to find [H+] from pH is [H+] = 10^(-pH).
Step 2: Since the pH is given as 4.0, calculate [H+] using the formula: [H+] = 10^(-4.0). This gives [H+] = 0.0001 M or 10^(-4) M.
Step 3: Identify the concentration of the weak acid (HA) which is given as 0.1 M.
Step 4: Use the formula for the acid dissociation constant (Ka): Ka = [H+]^2 / [HA].
Step 5: Substitute the values into the formula: Ka = (10^(-4))^2 / 0.1.
Step 6: Calculate (10^(-4))^2 which equals 10^(-8).
Step 7: Now divide 10^(-8) by 0.1 (which is the same as 10^(-1)): Ka = 10^(-8) / 10^(-1) = 10^(-8 + 1) = 10^(-7).
Step 8: Therefore, Ka = 1 x 10^(-7).
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