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In a zero-order reaction, if the rate constant k is 5 mol/L/s, how long will it

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Question: In a zero-order reaction, if the rate constant k is 5 mol/L/s, how long will it take for the concentration to decrease from 2 mol/L to 0 mol/L?

Options:

  1. 0.4 s
  2. 0.5 s
  3. 0.6 s
  4. 0.8 s

Correct Answer: 0.6 s

Solution: 

For a zero-order reaction, time = (initial concentration - final concentration) / k = (2 - 0) / 5 = 0.4 s.

In a zero-order reaction, if the rate constant k is 5 mol/L/s, how long will it

Practice Questions

Q1
In a zero-order reaction, if the rate constant k is 5 mol/L/s, how long will it take for the concentration to decrease from 2 mol/L to 0 mol/L?
  1. 0.4 s
  2. 0.5 s
  3. 0.6 s
  4. 0.8 s

Questions & Step-by-Step Solutions

In a zero-order reaction, if the rate constant k is 5 mol/L/s, how long will it take for the concentration to decrease from 2 mol/L to 0 mol/L?
  • Step 1: Identify the initial concentration, which is 2 mol/L.
  • Step 2: Identify the final concentration, which is 0 mol/L.
  • Step 3: Identify the rate constant k, which is 5 mol/L/s.
  • Step 4: Use the formula for time in a zero-order reaction: time = (initial concentration - final concentration) / k.
  • Step 5: Substitute the values into the formula: time = (2 mol/L - 0 mol/L) / 5 mol/L/s.
  • Step 6: Calculate the difference in concentration: 2 - 0 = 2 mol/L.
  • Step 7: Divide the difference by the rate constant: 2 mol/L / 5 mol/L/s = 0.4 s.
  • Step 8: Conclude that it will take 0.4 seconds for the concentration to decrease from 2 mol/L to 0 mol/L.
  • Zero-Order Reactions – In zero-order reactions, the rate of reaction is constant and does not depend on the concentration of the reactants.
  • Rate Constant (k) – The rate constant (k) is a proportionality factor that relates the rate of reaction to the concentration of reactants in zero-order kinetics.
  • Time Calculation – The time taken for a change in concentration in a zero-order reaction can be calculated using the formula: time = (initial concentration - final concentration) / k.
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