Question: What is the bond order of the molecule B2?
Options:
1
2
3
0
Correct Answer: 1
Solution:
B2 has a bond order of 1, calculated from its molecular orbital configuration.
What is the bond order of the molecule B2?
Practice Questions
Q1
What is the bond order of the molecule B2?
1
2
3
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Questions & Step-by-Step Solutions
What is the bond order of the molecule B2?
Step 1: Understand what bond order means. Bond order is a number that tells us how many bonds are between two atoms in a molecule.
Step 2: Know that B2 is a molecule made of two boron atoms.
Step 3: Find the total number of valence electrons for B2. Each boron atom has 3 valence electrons, so B2 has 3 + 3 = 6 valence electrons.
Step 4: Use the molecular orbital theory to fill the molecular orbitals with these 6 electrons. The order of filling is: sigma(1s), sigma*(1s), sigma(2s), sigma*(2s), sigma(2p), and pi(2p).
Step 5: Fill the orbitals: 2 electrons in sigma(1s), 2 electrons in sigma*(1s), 2 electrons in sigma(2s), and 0 in sigma*(2s) and pi(2p).
Step 6: Count the number of bonding and antibonding electrons. Bonding electrons are in sigma(1s), sigma(2s), and pi(2p) while antibonding electrons are in sigma*(1s) and sigma*(2s).
Step 7: For B2, there are 4 bonding electrons (2 in sigma(1s) and 2 in sigma(2s)) and 2 antibonding electrons (2 in sigma*(1s)).
Step 8: Use the bond order formula: Bond Order = (Number of bonding electrons - Number of antibonding electrons) / 2.
Step 9: Plug in the numbers: Bond Order = (4 - 2) / 2 = 2 / 2 = 1.
Step 10: Conclude that the bond order of the molecule B2 is 1.
Molecular Orbital Theory – Understanding how electrons are arranged in molecular orbitals to determine bond order.
Bond Order Calculation – The bond order is calculated as (number of bonding electrons - number of antibonding electrons) / 2.
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