What volume of 1 M NaOH solution is required to completely neutralize 0.5 moles

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Question: What volume of 1 M NaOH solution is required to completely neutralize 0.5 moles of HCl?

Options:

0.5 L
1 L
0.25 L
2 L

Correct Answer: 0.5 L

Solution:

The reaction between NaOH and HCl is 1:1. Therefore, to neutralize 0.5 moles of HCl, 0.5 moles of NaOH are required, which corresponds to 0.5 L of 1 M NaOH solution.

What volume of 1 M NaOH solution is required to completely neutralize 0.5 moles

Practice Questions

What volume of 1 M NaOH solution is required to completely neutralize 0.5 moles of HCl?

0.5 L
1 L
0.25 L
2 L

Questions & Step-by-Step Solutions

What volume of 1 M NaOH solution is required to completely neutralize 0.5 moles of HCl?

Step 1: Understand that NaOH (sodium hydroxide) and HCl (hydrochloric acid) react in a 1:1 ratio. This means 1 mole of NaOH can neutralize 1 mole of HCl.
Step 2: You have 0.5 moles of HCl that need to be neutralized.
Step 3: Since the ratio is 1:1, you will need 0.5 moles of NaOH to neutralize 0.5 moles of HCl.
Step 4: You are using a 1 M (molar) solution of NaOH. This means there is 1 mole of NaOH in 1 liter of solution.
Step 5: To find out how many liters of 1 M NaOH you need for 0.5 moles, use the formula: Volume (L) = Moles / Molarity.
Step 6: Plug in the values: Volume = 0.5 moles / 1 M = 0.5 L.
Step 7: Therefore, you need 0.5 liters of 1 M NaOH solution to completely neutralize 0.5 moles of HCl.

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What volume of 1 M NaOH solution is required to completely neutralize 0.5 moles

What’s inside this PDF?

What volume of 1 M NaOH solution is required to completely neutralize 0.5 moles

Practice Questions

Questions & Step-by-Step Solutions

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