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How many grams of KCl are needed to prepare 0.5 moles of KCl solution?

Practice Questions

1 question
Q1
How many grams of KCl are needed to prepare 0.5 moles of KCl solution?
  1. 37.5 g
  2. 74.5 g
  3. 50 g
  4. 100 g

Questions & Step-by-step Solutions

1 item
Q
Q: How many grams of KCl are needed to prepare 0.5 moles of KCl solution?
Solution: The molar mass of KCl is 39 g/mol (K) + 35.5 g/mol (Cl) = 74.5 g/mol. Therefore, 0.5 moles of KCl will weigh 0.5 x 74.5 g = 37.25 g.
Steps: 0

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