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A 4 kg object is moving with a speed of 5 m/s. If it comes to rest, what is the
A 4 kg object is moving with a speed of 5 m/s. If it comes to rest, what is the work done by friction?
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Q1
A 4 kg object is moving with a speed of 5 m/s. If it comes to rest, what is the work done by friction?
50 J
75 J
100 J
125 J
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Work done = change in kinetic energy = 0 - 0.5 × 4 kg × (5 m/s)² = -50 J.
Questions & Step-by-step Solutions
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Q
Q: A 4 kg object is moving with a speed of 5 m/s. If it comes to rest, what is the work done by friction?
Solution:
Work done = change in kinetic energy = 0 - 0.5 × 4 kg × (5 m/s)² = -50 J.
Steps: 9
Show Steps
Step 1: Identify the mass of the object, which is 4 kg.
Step 2: Identify the initial speed of the object, which is 5 m/s.
Step 3: Calculate the initial kinetic energy using the formula: Kinetic Energy = 0.5 × mass × (speed)².
Step 4: Substitute the values into the formula: Kinetic Energy = 0.5 × 4 kg × (5 m/s)².
Step 5: Calculate (5 m/s)², which is 25 m²/s².
Step 6: Multiply 0.5 × 4 kg × 25 m²/s² to get 50 J.
Step 7: The object comes to rest, so the final kinetic energy is 0 J.
Step 8: Calculate the change in kinetic energy: Final KE - Initial KE = 0 J - 50 J.
Step 9: The change in kinetic energy is -50 J, which represents the work done by friction.
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