A 10 kg object falls from a height of 20 m. What is its speed just before it hit

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Question: A 10 kg object falls from a height of 20 m. What is its speed just before it hits the ground?

Options:

Correct Answer: 20 m/s

Solution:

Using conservation of energy, v = √(2gh) = √(2 * 9.8 * 20) = 20 m/s.

A 10 kg object falls from a height of 20 m. What is its speed just before it hits the ground?

A 10 kg object falls from a height of 20 m. What is its speed just before it hits the ground?

Step 1: Identify the height from which the object falls. In this case, it is 20 meters.
Step 2: Identify the acceleration due to gravity, which is approximately 9.8 m/s².
Step 3: Use the formula for speed just before hitting the ground, which is v = √(2gh).
Step 4: Substitute the values into the formula: v = √(2 * 9.8 * 20).
Step 5: Calculate the value inside the square root: 2 * 9.8 * 20 = 392.
Step 6: Take the square root of 392 to find the speed: v = √392.
Step 7: Calculate √392, which is approximately 19.8 m/s, rounded to 20 m/s.

Conservation of Energy – The principle that the total energy in a closed system remains constant; in this case, potential energy is converted to kinetic energy as the object falls.
Kinematics – The study of motion, specifically how the speed of an object changes as it falls under the influence of gravity.