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If a force of 12 N is applied at an angle of 30 degrees to a lever arm of 1 m, what is the torque about the pivot?

Practice Questions

1 question
Q1
If a force of 12 N is applied at an angle of 30 degrees to a lever arm of 1 m, what is the torque about the pivot?
  1. 6 Nm
  2. 10 Nm
  3. 12 Nm
  4. 15 Nm

Questions & Step-by-step Solutions

1 item
Q
Q: If a force of 12 N is applied at an angle of 30 degrees to a lever arm of 1 m, what is the torque about the pivot?
Solution: Torque = Force × Distance × sin(θ) = 12 N × 1 m × sin(30°) = 12 N × 1 m × 0.5 = 6 Nm.
Steps: 0

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