If a force of 12 N is applied at an angle of 30 degrees to a lever arm of 1 m, w

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Question: If a force of 12 N is applied at an angle of 30 degrees to a lever arm of 1 m, what is the torque about the pivot?

Options:

Correct Answer: 6 Nm

Solution:

Torque = Force × Distance × sin(θ) = 12 N × 1 m × sin(30°) = 12 N × 1 m × 0.5 = 6 Nm.

If a force of 12 N is applied at an angle of 30 degrees to a lever arm of 1 m, what is the torque about the pivot?

If a force of 12 N is applied at an angle of 30 degrees to a lever arm of 1 m, what is the torque about the pivot?

Step 1: Identify the force applied, which is 12 N.
Step 2: Identify the distance from the pivot to where the force is applied, which is 1 m.
Step 3: Identify the angle at which the force is applied, which is 30 degrees.
Step 4: Use the formula for torque: Torque = Force × Distance × sin(θ).
Step 5: Substitute the values into the formula: Torque = 12 N × 1 m × sin(30°).
Step 6: Calculate sin(30°), which is 0.5.
Step 7: Multiply the values: Torque = 12 N × 1 m × 0.5.
Step 8: Calculate the final result: Torque = 6 Nm.

Torque – Torque is the rotational equivalent of linear force, calculated as the product of the force applied, the distance from the pivot point, and the sine of the angle between the force and the lever arm.
Trigonometric Functions – Understanding how to use sine in the context of angles is crucial for calculating torque when the force is applied at an angle.
Units of Measurement – Recognizing that torque is measured in Newton-meters (Nm) and ensuring that all units are consistent in calculations.