What is the torque produced by a force of 15 N acting at an angle of 90 degrees

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Question: What is the torque produced by a force of 15 N acting at an angle of 90 degrees to the lever arm of 0.5 m?

Options:

Correct Answer: 15 Nm

Solution:

Torque = Force × Distance × sin(θ) = 15 N × 0.5 m × sin(90°) = 15 Nm.

What is the torque produced by a force of 15 N acting at an angle of 90 degrees to the lever arm of 0.5 m?

What is the torque produced by a force of 15 N acting at an angle of 90 degrees to the lever arm of 0.5 m?

Step 1: Identify the force applied, which is 15 N.
Step 2: Identify the distance from the pivot point to where the force is applied, which is 0.5 m.
Step 3: Identify the angle at which the force is applied, which is 90 degrees.
Step 4: Use the formula for torque: Torque = Force × Distance × sin(θ).
Step 5: Substitute the values into the formula: Torque = 15 N × 0.5 m × sin(90°).
Step 6: Calculate sin(90°), which is 1.
Step 7: Multiply the values: Torque = 15 N × 0.5 m × 1.
Step 8: Calculate the final result: Torque = 15 Nm.

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