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What is the torque produced by a force of 15 N acting at an angle of 90 degrees to the lever arm of 0.5 m?

Practice Questions

1 question
Q1
What is the torque produced by a force of 15 N acting at an angle of 90 degrees to the lever arm of 0.5 m?
  1. 0 Nm
  2. 7.5 Nm
  3. 15 Nm
  4. 30 Nm

Questions & Step-by-step Solutions

1 item
Q
Q: What is the torque produced by a force of 15 N acting at an angle of 90 degrees to the lever arm of 0.5 m?
Solution: Torque = Force × Distance × sin(θ) = 15 N × 0.5 m × sin(90°) = 15 Nm.
Steps: 0

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