For a thin circular ring of mass M and radius R, what is the moment of inertia about an axis perpendicular to its plane through its center?
Practice Questions
1 question
Q1
For a thin circular ring of mass M and radius R, what is the moment of inertia about an axis perpendicular to its plane through its center?
MR^2
1/2 MR^2
2/3 MR^2
1/3 MR^2
The moment of inertia of a thin circular ring about an axis through its center and perpendicular to its plane is I = MR^2.
Questions & Step-by-step Solutions
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Q
Q: For a thin circular ring of mass M and radius R, what is the moment of inertia about an axis perpendicular to its plane through its center?
Solution: The moment of inertia of a thin circular ring about an axis through its center and perpendicular to its plane is I = MR^2.
Steps: 5
Step 1: Understand what moment of inertia means. It is a measure of how difficult it is to change the rotation of an object.
Step 2: Identify the shape of the object. In this case, it is a thin circular ring.
Step 3: Recognize the mass (M) and radius (R) of the ring. These are important for calculating the moment of inertia.
Step 4: Recall the formula for the moment of inertia of a thin circular ring about an axis through its center and perpendicular to its plane, which is I = MR^2.
Step 5: Substitute the values of mass (M) and radius (R) into the formula to find the moment of inertia.
