Question: A disk of radius R and mass M is rotating about its axis with an angular velocity ω. What is its kinetic energy?
Options:
Correct Answer: (1/2)Iω^2
Solution:
The moment of inertia I of a disk about its axis is (1/2)MR^2. Therefore, the kinetic energy K.E. = (1/2)Iω^2 = (1/2)(1/2)MR^2ω^2 = (1/4)MR^2ω^2.