A simple harmonic oscillator has a maximum displacement of 0.1 m. What is the ma

A simple harmonic oscillator has a maximum displacement of 0.1 m. What is the maximum potential energy if the spring constant is 200 N/m?

A simple harmonic oscillator has a maximum displacement of 0.1 m. What is the maximum potential energy if the spring constant is 200 N/m?

Step 1: Identify the formula for maximum potential energy (PE) in a simple harmonic oscillator, which is PE = (1/2)kA^2.
Step 2: Identify the values needed for the formula: the spring constant (k) is 200 N/m and the maximum displacement (A) is 0.1 m.
Step 3: Substitute the values into the formula: PE = (1/2)(200)(0.1^2).
Step 4: Calculate 0.1^2, which is 0.01.
Step 5: Multiply 200 by 0.01 to get 2.
Step 6: Multiply 2 by (1/2) to get 1.
Step 7: Conclude that the maximum potential energy is 1 J.

Simple Harmonic Motion – Understanding the principles of simple harmonic motion, including maximum displacement and potential energy.
Potential Energy in Springs – Application of the formula for potential energy stored in a spring, PE = (1/2)kA^2.