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A simple harmonic oscillator has a maximum displacement of 0.1 m. What is the ma

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Question: A simple harmonic oscillator has a maximum displacement of 0.1 m. What is the maximum potential energy if the spring constant is 200 N/m?

Options:

  1. 1 J
  2. 2 J
  3. 3 J
  4. 4 J

Correct Answer: 2 J

Solution: 

Maximum potential energy (PE) = (1/2)kA^2 = (1/2)(200)(0.1^2) = 1 J.

A simple harmonic oscillator has a maximum displacement of 0.1 m. What is the ma

Practice Questions

Q1
A simple harmonic oscillator has a maximum displacement of 0.1 m. What is the maximum potential energy if the spring constant is 200 N/m?
  1. 1 J
  2. 2 J
  3. 3 J
  4. 4 J

Questions & Step-by-Step Solutions

A simple harmonic oscillator has a maximum displacement of 0.1 m. What is the maximum potential energy if the spring constant is 200 N/m?
  • Step 1: Identify the formula for maximum potential energy (PE) in a simple harmonic oscillator, which is PE = (1/2)kA^2.
  • Step 2: Identify the values needed for the formula: the spring constant (k) is 200 N/m and the maximum displacement (A) is 0.1 m.
  • Step 3: Substitute the values into the formula: PE = (1/2)(200)(0.1^2).
  • Step 4: Calculate 0.1^2, which is 0.01.
  • Step 5: Multiply 200 by 0.01 to get 2.
  • Step 6: Multiply 2 by (1/2) to get 1.
  • Step 7: Conclude that the maximum potential energy is 1 J.
  • Simple Harmonic Motion – Understanding the principles of simple harmonic motion, including maximum displacement and potential energy.
  • Potential Energy in Springs – Application of the formula for potential energy stored in a spring, PE = (1/2)kA^2.
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