A fiber optic cable uses total internal reflection. If the refractive index of the core is 1.5 and that of the cladding is 1.4, what is the critical angle?

Practice Questions

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42.0°
48.6°
60.0°
30.0°

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Q: A fiber optic cable uses total internal reflection. If the refractive index of the core is 1.5 and that of the cladding is 1.4, what is the critical angle?

Solution: Critical angle θc = sin⁻¹(n2/n1) = sin⁻¹(1.4/1.5) ≈ 42.0°.

Steps: 6

Step 1: Identify the refractive indices. The refractive index of the core (n1) is 1.5 and the refractive index of the cladding (n2) is 1.4.
Step 2: Use the formula for the critical angle, which is θc = sin⁻¹(n2/n1).
Step 3: Substitute the values into the formula: θc = sin⁻¹(1.4/1.5).
Step 4: Calculate the value of 1.4 divided by 1.5, which is approximately 0.9333.
Step 5: Find the inverse sine (sin⁻¹) of 0.9333 using a calculator or trigonometric table.
Step 6: The result is approximately 42.0 degrees, which is the critical angle.

A fiber optic cable uses total internal reflection. If the refractive index of the core is 1.5 and that of the cladding is 1.4, what is the critical angle?

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