A beam of light in diamond (n=2.42) strikes the surface of water (n=1.33). What

Practice Questions

Q1
A beam of light in diamond (n=2.42) strikes the surface of water (n=1.33). What is the critical angle for total internal reflection?
  1. 25.5°
  2. 30.0°
  3. 36.9°
  4. 42.0°

Questions & Step-by-Step Solutions

A beam of light in diamond (n=2.42) strikes the surface of water (n=1.33). What is the critical angle for total internal reflection?
  • Step 1: Identify the refractive indices of the two materials. For diamond, n1 = 2.42 and for water, n2 = 1.33.
  • Step 2: Use the formula for critical angle, which is θc = sin⁻¹(n2/n1).
  • Step 3: Substitute the values into the formula: θc = sin⁻¹(1.33/2.42).
  • Step 4: Calculate the value of 1.33 divided by 2.42, which is approximately 0.549.
  • Step 5: Find the inverse sine (sin⁻¹) of 0.549 using a calculator, which gives approximately 36.9°.
  • Step 6: Conclude that the critical angle for total internal reflection is about 36.9°.
  • Snell's Law and Critical Angle – The critical angle is the angle of incidence above which total internal reflection occurs, calculated using the refractive indices of the two media.
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