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An object is placed at a distance of 15 cm from a convex lens of focal length 10

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Question: An object is placed at a distance of 15 cm from a convex lens of focal length 10 cm. Where is the image formed?

Options:

  1. 5 cm
  2. 10 cm
  3. 15 cm
  4. 20 cm

Correct Answer: 20 cm

Solution:

Using the lens formula, 1/f = 1/v - 1/u, we find v = 30 cm, meaning the image is formed 30 cm on the opposite side.

An object is placed at a distance of 15 cm from a convex lens of focal length 10

Practice Questions

Q1
An object is placed at a distance of 15 cm from a convex lens of focal length 10 cm. Where is the image formed?
  1. 5 cm
  2. 10 cm
  3. 15 cm
  4. 20 cm

Questions & Step-by-Step Solutions

An object is placed at a distance of 15 cm from a convex lens of focal length 10 cm. Where is the image formed?
  • Step 1: Identify the given values. The object distance (u) is -15 cm (negative because it is on the same side as the object) and the focal length (f) is +10 cm (positive for a convex lens).
  • Step 2: Write down the lens formula: 1/f = 1/v - 1/u.
  • Step 3: Substitute the known values into the lens formula: 1/10 = 1/v - 1/(-15).
  • Step 4: Simplify the equation: 1/10 = 1/v + 1/15.
  • Step 5: Find a common denominator for the right side, which is 30. Rewrite the equation: 1/10 = 1/v + 2/30.
  • Step 6: Convert 1/10 to have a denominator of 30: 3/30 = 1/v + 2/30.
  • Step 7: Rearrange the equation: 3/30 - 2/30 = 1/v, which simplifies to 1/30 = 1/v.
  • Step 8: Take the reciprocal to find v: v = 30 cm.
  • Step 9: Interpret the result: The image is formed 30 cm on the opposite side of the lens.
  • Lens Formula – The lens formula relates the focal length (f), object distance (u), and image distance (v) of a lens, expressed as 1/f = 1/v - 1/u.
  • Convex Lens Properties – A convex lens converges light rays and can form real and virtual images depending on the position of the object relative to the focal length.
  • Sign Convention – Understanding the sign convention for distances in optics is crucial, where object distance is negative for real objects placed on the same side as the incoming light.
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