In a thin film of soap, if the refractive index is 1.33 and the wavelength of li
Practice Questions
Q1
In a thin film of soap, if the refractive index is 1.33 and the wavelength of light in air is 500 nm, what is the effective wavelength in the film?
375 nm
500 nm
600 nm
750 nm
Questions & Step-by-Step Solutions
In a thin film of soap, if the refractive index is 1.33 and the wavelength of light in air is 500 nm, what is the effective wavelength in the film?
Step 1: Understand that the refractive index (n) of a material affects the speed of light in that material.
Step 2: Know that the wavelength of light changes when it enters a different medium, and it can be calculated using the formula: effective wavelength in the film = wavelength in air / refractive index.
Step 3: Identify the given values: the wavelength in air (λ) is 500 nm and the refractive index (n) is 1.33.
Step 4: Plug the values into the formula: effective wavelength in the film = 500 nm / 1.33.
Step 5: Perform the division: 500 nm divided by 1.33 equals approximately 375 nm.
Step 6: Conclude that the effective wavelength of light in the soap film is about 375 nm.
