In a double-slit experiment, if the distance between the slits is 0.2 mm and the
Practice Questions
Q1
In a double-slit experiment, if the distance between the slits is 0.2 mm and the distance to the screen is 1 m, what is the fringe width for light of wavelength 600 nm?
0.3 mm
0.6 mm
0.9 mm
1.2 mm
Questions & Step-by-Step Solutions
In a double-slit experiment, if the distance between the slits is 0.2 mm and the distance to the screen is 1 m, what is the fringe width for light of wavelength 600 nm?
Step 1: Identify the given values from the problem. The distance between the slits (d) is 0.2 mm, the distance to the screen (D) is 1 m, and the wavelength of light (λ) is 600 nm.
Step 2: Convert all measurements to meters for consistency. 0.2 mm = 0.2 x 10^-3 m and 600 nm = 600 x 10^-9 m.
Step 3: Use the formula for fringe width (β): β = λD/d.
Step 4: Substitute the values into the formula: β = (600 x 10^-9 m)(1 m) / (0.2 x 10^-3 m).
Step 5: Calculate the numerator: 600 x 10^-9 m * 1 m = 600 x 10^-9 m.
Step 6: Calculate the denominator: 0.2 x 10^-3 m = 0.0002 m.
Step 7: Divide the numerator by the denominator: β = (600 x 10^-9 m) / (0.0002 m).
Step 8: Perform the division: β = 0.003 m.
Step 9: Convert the result back to mm: 0.003 m = 0.6 mm.
