Question: In a double-slit experiment, if the distance between the slits is 0.2 mm and the distance to the screen is 1 m, what is the fringe width for light of wavelength 600 nm?
Options:
Correct Answer: 0.6 mm
Solution:
Fringe width β = λD/d = (600 x 10^-9 m)(1 m)/(0.2 x 10^-3 m) = 0.003 m = 0.6 mm.