What is the magnetic field inside a solenoid carrying current I with n turns per unit length?

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Q: What is the magnetic field inside a solenoid carrying current I with n turns per unit length?

Solution: The magnetic field inside a long solenoid is given by B = μ₀nI.

Steps: 5

Step 1: Understand what a solenoid is. A solenoid is a coil of wire that creates a magnetic field when an electric current passes through it.
Step 2: Identify the variables in the formula. In the formula B = μ₀nI, B is the magnetic field, μ₀ is the permeability of free space (a constant), n is the number of turns of the wire per unit length, and I is the current flowing through the wire.
Step 3: Recognize that the magnetic field inside a long solenoid is uniform and directed along the axis of the solenoid.
Step 4: Use the formula B = μ₀nI to calculate the magnetic field. You need to know the values of n (turns per unit length) and I (current) to find B.
Step 5: Remember that this formula applies specifically to long solenoids, where the length is much greater than the diameter.