A 12 kg object is pulled with a force of 24 N. If the object experiences a frictional force of 4 N, what is its acceleration?

1 question

1 item

Q: A 12 kg object is pulled with a force of 24 N. If the object experiences a frictional force of 4 N, what is its acceleration?

Solution: Net force = 24 N - 4 N = 20 N. Acceleration a = F/m = 20 N / 12 kg = 1.67 m/s².

Steps: 9

Step 1: Identify the mass of the object, which is 12 kg.
Step 2: Identify the pulling force applied to the object, which is 24 N.
Step 3: Identify the frictional force acting against the motion, which is 4 N.
Step 4: Calculate the net force by subtracting the frictional force from the pulling force: Net force = 24 N - 4 N.
Step 5: Perform the subtraction: 24 N - 4 N = 20 N. So, the net force is 20 N.
Step 6: Use the formula for acceleration, which is a = F/m, where F is the net force and m is the mass.
Step 7: Substitute the values into the formula: a = 20 N / 12 kg.
Step 8: Perform the division: 20 N / 12 kg = 1.67 m/s².
Step 9: Conclude that the acceleration of the object is 1.67 m/s².