A 15 kg box is pushed with a force of 30 N. If the frictional force opposing the motion is 10 N, what is the acceleration of the box?

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Q: A 15 kg box is pushed with a force of 30 N. If the frictional force opposing the motion is 10 N, what is the acceleration of the box?

Solution: Net force = applied force - friction = 30 N - 10 N = 20 N. Acceleration a = F/m = 20 N / 15 kg = 1.33 m/s².

Steps: 9

Step 1: Identify the mass of the box, which is 15 kg.
Step 2: Identify the applied force pushing the box, which is 30 N.
Step 3: Identify the frictional force opposing the motion, which is 10 N.
Step 4: Calculate the net force acting on the box by subtracting the frictional force from the applied force: Net force = 30 N - 10 N.
Step 5: Perform the subtraction: 30 N - 10 N = 20 N. So, the net force is 20 N.
Step 6: Use the formula for acceleration, which is acceleration (a) = net force (F) / mass (m).
Step 7: Substitute the values into the formula: a = 20 N / 15 kg.
Step 8: Perform the division: 20 N / 15 kg = 1.33 m/s².
Step 9: Conclude that the acceleration of the box is 1.33 m/s².