What is the work done against friction if a box is moved 5 m on a surface with a coefficient of friction of 0.2 and a normal force of 200 N?

Practice Questions

1 question
Q1
What is the work done against friction if a box is moved 5 m on a surface with a coefficient of friction of 0.2 and a normal force of 200 N?
  1. 10 J
  2. 20 J
  3. 30 J
  4. 40 J

Questions & Step-by-step Solutions

1 item
Q
Q: What is the work done against friction if a box is moved 5 m on a surface with a coefficient of friction of 0.2 and a normal force of 200 N?
Solution: Frictional force = μ * N = 0.2 * 200 N = 40 N. Work done = frictional force * distance = 40 N * 5 m = 200 J.
Steps: 0

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