What is the work done against friction if a box is moved 5 m on a surface with a

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Question: What is the work done against friction if a box is moved 5 m on a surface with a coefficient of friction of 0.2 and a normal force of 200 N?

Options:

10 J
20 J
30 J
40 J

Correct Answer: 20 J

Solution:

Frictional force = μ * N = 0.2 * 200 N = 40 N. Work done = frictional force * distance = 40 N * 5 m = 200 J.

What is the work done against friction if a box is moved 5 m on a surface with a

Practice Questions

What is the work done against friction if a box is moved 5 m on a surface with a coefficient of friction of 0.2 and a normal force of 200 N?

10 J
20 J
30 J
40 J

Questions & Step-by-Step Solutions

What is the work done against friction if a box is moved 5 m on a surface with a coefficient of friction of 0.2 and a normal force of 200 N?

Step 1: Identify the coefficient of friction (μ), which is given as 0.2.
Step 2: Identify the normal force (N), which is given as 200 N.
Step 3: Calculate the frictional force using the formula: Frictional force = μ * N.
Step 4: Substitute the values: Frictional force = 0.2 * 200 N.
Step 5: Calculate the frictional force: Frictional force = 40 N.
Step 6: Identify the distance the box is moved, which is given as 5 m.
Step 7: Calculate the work done against friction using the formula: Work done = frictional force * distance.
Step 8: Substitute the values: Work done = 40 N * 5 m.
Step 9: Calculate the work done: Work done = 200 J.

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What is the work done against friction if a box is moved 5 m on a surface with a

What’s inside this PDF?

What is the work done against friction if a box is moved 5 m on a surface with a

Practice Questions

Questions & Step-by-Step Solutions

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