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A block of mass 5 kg is resting on a horizontal surface. If the coefficient of k

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Question: A block of mass 5 kg is resting on a horizontal surface. If the coefficient of kinetic friction between the block and the surface is 0.3, what is the frictional force acting on the block when it is sliding?

Options:

  1. 5 N
  2. 10 N
  3. 15 N
  4. 20 N

Correct Answer: 10 N

Solution: 

Frictional force (Ff) = μk * N = μk * mg = 0.3 * (5 kg * 10 m/s²) = 15 N.

A block of mass 5 kg is resting on a horizontal surface. If the coefficient of k

Practice Questions

Q1
A block of mass 5 kg is resting on a horizontal surface. If the coefficient of kinetic friction between the block and the surface is 0.3, what is the frictional force acting on the block when it is sliding?
  1. 5 N
  2. 10 N
  3. 15 N
  4. 20 N

Questions & Step-by-Step Solutions

A block of mass 5 kg is resting on a horizontal surface. If the coefficient of kinetic friction between the block and the surface is 0.3, what is the frictional force acting on the block when it is sliding?
  • Step 1: Identify the mass of the block, which is given as 5 kg.
  • Step 2: Identify the coefficient of kinetic friction (μk), which is given as 0.3.
  • Step 3: Calculate the weight of the block (N), which is the force due to gravity. Use the formula: N = mass (m) * gravity (g). Here, g is approximately 10 m/s².
  • Step 4: Substitute the values into the formula: N = 5 kg * 10 m/s² = 50 N.
  • Step 5: Now, calculate the frictional force (Ff) using the formula: Ff = μk * N.
  • Step 6: Substitute the values into the formula: Ff = 0.3 * 50 N.
  • Step 7: Calculate the result: Ff = 15 N.
  • Frictional Force – The force that opposes the motion of an object sliding on a surface, calculated using the coefficient of kinetic friction and the normal force.
  • Normal Force – The force exerted by a surface to support the weight of an object resting on it, equal to the weight of the object when on a horizontal surface.
  • Coefficient of Kinetic Friction – A dimensionless constant that represents the ratio of the force of friction between two bodies and the force pressing them together.
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