A block of mass 5 kg is resting on a horizontal surface. If the coefficient of kinetic friction between the block and the surface is 0.3, what is the frictional force acting on the block when it is sliding?
Practice Questions
1 question
Q1
A block of mass 5 kg is resting on a horizontal surface. If the coefficient of kinetic friction between the block and the surface is 0.3, what is the frictional force acting on the block when it is sliding?
5 N
10 N
15 N
20 N
Frictional force (Ff) = μk * N = μk * mg = 0.3 * (5 kg * 10 m/s²) = 15 N.
Questions & Step-by-step Solutions
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Q
Q: A block of mass 5 kg is resting on a horizontal surface. If the coefficient of kinetic friction between the block and the surface is 0.3, what is the frictional force acting on the block when it is sliding?
Solution: Frictional force (Ff) = μk * N = μk * mg = 0.3 * (5 kg * 10 m/s²) = 15 N.
Steps: 7
Step 1: Identify the mass of the block, which is given as 5 kg.
Step 2: Identify the coefficient of kinetic friction (μk), which is given as 0.3.
Step 3: Calculate the weight of the block (N), which is the force due to gravity. Use the formula: N = mass (m) * gravity (g). Here, g is approximately 10 m/s².
Step 4: Substitute the values into the formula: N = 5 kg * 10 m/s² = 50 N.
Step 5: Now, calculate the frictional force (Ff) using the formula: Ff = μk * N.
Step 6: Substitute the values into the formula: Ff = 0.3 * 50 N.
