A block of mass 5 kg is resting on a horizontal surface. If the coefficient of k
Practice Questions
Q1
A block of mass 5 kg is resting on a horizontal surface. If the coefficient of kinetic friction between the block and the surface is 0.3, what is the frictional force acting on the block when it is sliding?
5 N
10 N
15 N
20 N
Questions & Step-by-Step Solutions
A block of mass 5 kg is resting on a horizontal surface. If the coefficient of kinetic friction between the block and the surface is 0.3, what is the frictional force acting on the block when it is sliding?
Step 1: Identify the mass of the block, which is given as 5 kg.
Step 2: Identify the coefficient of kinetic friction (μk), which is given as 0.3.
Step 3: Calculate the weight of the block (N), which is the force due to gravity. Use the formula: N = mass (m) * gravity (g). Here, g is approximately 10 m/s².
Step 4: Substitute the values into the formula: N = 5 kg * 10 m/s² = 50 N.
Step 5: Now, calculate the frictional force (Ff) using the formula: Ff = μk * N.
Step 6: Substitute the values into the formula: Ff = 0.3 * 50 N.
Step 7: Calculate the result: Ff = 15 N.
Frictional Force – The force that opposes the motion of an object sliding on a surface, calculated using the coefficient of kinetic friction and the normal force.
Normal Force – The force exerted by a surface to support the weight of an object resting on it, equal to the weight of the object when on a horizontal surface.
Coefficient of Kinetic Friction – A dimensionless constant that represents the ratio of the force of friction between two bodies and the force pressing them together.
