What is the impedance of a series circuit containing a resistor and an inductor?

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Question: What is the impedance of a series circuit containing a resistor and an inductor?

Options:

Correct Answer: √(R^2 + (ωL)^2)

Solution:

The impedance Z in a series R-L circuit is given by Z = √(R^2 + (ωL)^2).

What is the impedance of a series circuit containing a resistor and an inductor?

What is the impedance of a series circuit containing a resistor and an inductor?

Step 1: Identify the components in the circuit. You have a resistor (R) and an inductor (L).
Step 2: Understand that impedance (Z) is a measure of how much the circuit resists the flow of electric current.
Step 3: Recognize that in a series circuit, the total impedance is affected by both the resistance of the resistor and the reactance of the inductor.
Step 4: The reactance of the inductor is calculated using the formula ωL, where ω (omega) is the angular frequency of the AC signal.
Step 5: Use the formula for impedance in a series R-L circuit: Z = √(R^2 + (ωL)^2).
Step 6: Plug in the values for R and L, and the frequency to calculate the impedance Z.

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