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A 5 kg object is thrown vertically upward with a speed of 20 m/s. What is the ma
A 5 kg object is thrown vertically upward with a speed of 20 m/s. What is the maximum height reached by the object? (g = 10 m/s²)
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A 5 kg object is thrown vertically upward with a speed of 20 m/s. What is the maximum height reached by the object? (g = 10 m/s²)
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Using the formula h = v²/(2g) = (20 m/s)² / (2 * 10 m/s²) = 20 m.
Questions & Step-by-step Solutions
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Q: A 5 kg object is thrown vertically upward with a speed of 20 m/s. What is the maximum height reached by the object? (g = 10 m/s²)
Solution:
Using the formula h = v²/(2g) = (20 m/s)² / (2 * 10 m/s²) = 20 m.
Steps: 8
Show Steps
Step 1: Identify the initial speed (v) of the object, which is 20 m/s.
Step 2: Identify the acceleration due to gravity (g), which is 10 m/s².
Step 3: Use the formula for maximum height (h) reached by an object thrown upward: h = v² / (2g).
Step 4: Substitute the values into the formula: h = (20 m/s)² / (2 * 10 m/s²).
Step 5: Calculate (20 m/s)², which equals 400 m²/s².
Step 6: Calculate 2 * 10 m/s², which equals 20 m/s².
Step 7: Divide 400 m²/s² by 20 m/s² to find h: 400 m²/s² / 20 m/s² = 20 m.
Step 8: Conclude that the maximum height reached by the object is 20 meters.
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