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A 10 kg object is dropped from a height. What is the force acting on it just bef
A 10 kg object is dropped from a height. What is the force acting on it just before it hits the ground?
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A 10 kg object is dropped from a height. What is the force acting on it just before it hits the ground?
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The force acting on the object is its weight, F = mg = 10 kg * 10 m/s² = 100 N.
Questions & Step-by-step Solutions
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Q
Q: A 10 kg object is dropped from a height. What is the force acting on it just before it hits the ground?
Solution:
The force acting on the object is its weight, F = mg = 10 kg * 10 m/s² = 100 N.
Steps: 6
Show Steps
Step 1: Identify the mass of the object. In this case, the mass is 10 kg.
Step 2: Understand that the force acting on the object just before it hits the ground is its weight.
Step 3: Use the formula for weight, which is F = mg, where F is the force, m is the mass, and g is the acceleration due to gravity.
Step 4: Substitute the values into the formula. Here, m = 10 kg and g = 10 m/s².
Step 5: Calculate the force: F = 10 kg * 10 m/s² = 100 N.
Step 6: Conclude that the force acting on the object just before it hits the ground is 100 N.
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