A 6 kg object is dropped from a height. What is the force acting on it just befo

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Question: A 6 kg object is dropped from a height. What is the force acting on it just before it hits the ground?

Options:

Correct Answer: 60 N

Solution:

The force acting on it is its weight, F = mg = 6 kg * 10 m/s² = 60 N.

A 6 kg object is dropped from a height. What is the force acting on it just before it hits the ground?

A 6 kg object is dropped from a height. What is the force acting on it just before it hits the ground?

Step 1: Identify the mass of the object. In this case, the mass is 6 kg.
Step 2: Understand that the force acting on the object just before it hits the ground is its weight.
Step 3: Use the formula for weight, which is F = mg, where F is the force, m is the mass, and g is the acceleration due to gravity.
Step 4: Substitute the values into the formula. Here, m = 6 kg and g = 10 m/s².
Step 5: Calculate the force: F = 6 kg * 10 m/s² = 60 N.
Step 6: Conclude that the force acting on the object just before it hits the ground is 60 N.

Weight – The force acting on an object due to gravity, calculated as the product of mass and gravitational acceleration (F = mg).
Gravitational Acceleration – The acceleration due to gravity, typically approximated as 10 m/s² for simplicity in calculations.