A ball is thrown at an angle of 45 degrees with an initial speed of 28 m/s. What is the vertical component of the velocity at the peak of its trajectory?
Practice Questions
1 question
Q1
A ball is thrown at an angle of 45 degrees with an initial speed of 28 m/s. What is the vertical component of the velocity at the peak of its trajectory?
0 m/s
14 m/s
20 m/s
28 m/s
At the peak, the vertical component of velocity is 0 m/s.
Questions & Step-by-step Solutions
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Q
Q: A ball is thrown at an angle of 45 degrees with an initial speed of 28 m/s. What is the vertical component of the velocity at the peak of its trajectory?
Solution: At the peak, the vertical component of velocity is 0 m/s.
Steps: 3
Step 1: Understand that when a ball is thrown at an angle, it has two components of velocity: vertical (up and down) and horizontal (side to side).
Step 2: Recognize that at the peak of the ball's trajectory (the highest point), the vertical component of the velocity becomes 0 m/s because the ball stops moving upward and is about to start falling down.
Step 3: Conclude that regardless of the initial speed or angle, at the peak, the vertical component of the velocity is always 0 m/s.
