A stone is dropped from a height of 45 m. How far will it travel horizontally if it is thrown horizontally with a speed of 10 m/s?
Practice Questions
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Q1
A stone is dropped from a height of 45 m. How far will it travel horizontally if it is thrown horizontally with a speed of 10 m/s?
20 m
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50 m
Time to fall (t) = √(2h/g) = √(2*45/9.8) ≈ 3 s; horizontal distance = v*t = 10*3 = 30 m.
Questions & Step-by-step Solutions
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Q
Q: A stone is dropped from a height of 45 m. How far will it travel horizontally if it is thrown horizontally with a speed of 10 m/s?
Solution: Time to fall (t) = √(2h/g) = √(2*45/9.8) ≈ 3 s; horizontal distance = v*t = 10*3 = 30 m.
Steps: 7
Step 1: Identify the height from which the stone is dropped, which is 45 meters.
Step 2: Use the formula to calculate the time it takes for the stone to fall. The formula is t = √(2h/g), where h is the height (45 m) and g is the acceleration due to gravity (approximately 9.8 m/s²).
Step 3: Plug in the values into the formula: t = √(2*45/9.8).
Step 4: Calculate the value inside the square root: 2*45 = 90, then divide by 9.8 to get approximately 9.18.
Step 5: Take the square root of 9.18 to find the time t, which is approximately 3 seconds.
Step 6: Now, calculate the horizontal distance traveled using the formula: distance = speed * time. The speed is given as 10 m/s.
Step 7: Multiply the speed (10 m/s) by the time (3 s) to find the horizontal distance: 10 * 3 = 30 meters.
