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If a gas occupies a volume of 10 L at 1 atm, what will be its volume at 2 atm if
If a gas occupies a volume of 10 L at 1 atm, what will be its volume at 2 atm if the temperature remains constant?
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Q1
If a gas occupies a volume of 10 L at 1 atm, what will be its volume at 2 atm if the temperature remains constant?
5 L
10 L
20 L
15 L
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Using Boyle's Law (P1V1 = P2V2), if the pressure doubles from 1 atm to 2 atm, the volume will halve from 10 L to 5 L.
Questions & Step-by-step Solutions
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Q: If a gas occupies a volume of 10 L at 1 atm, what will be its volume at 2 atm if the temperature remains constant?
Solution:
Using Boyle's Law (P1V1 = P2V2), if the pressure doubles from 1 atm to 2 atm, the volume will halve from 10 L to 5 L.
Steps: 7
Show Steps
Step 1: Identify the initial conditions. The initial pressure (P1) is 1 atm and the initial volume (V1) is 10 L.
Step 2: Identify the final pressure (P2). The final pressure is 2 atm.
Step 3: Use Boyle's Law formula, which states that P1 * V1 = P2 * V2.
Step 4: Substitute the known values into the formula: 1 atm * 10 L = 2 atm * V2.
Step 5: Solve for V2. Rearrange the equation to find V2: V2 = (1 atm * 10 L) / (2 atm).
Step 6: Calculate V2: V2 = 10 L / 2 = 5 L.
Step 7: Conclude that if the pressure doubles, the volume halves, so the final volume is 5 L.
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