If a gas occupies a volume of 10 L at 1 atm, what will be its volume at 2 atm if

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Question: If a gas occupies a volume of 10 L at 1 atm, what will be its volume at 2 atm if the temperature remains constant?

Options:

Correct Answer: 5 L

Solution:

Using Boyle\'s Law (P1V1 = P2V2), if the pressure doubles from 1 atm to 2 atm, the volume will halve from 10 L to 5 L.

If a gas occupies a volume of 10 L at 1 atm, what will be its volume at 2 atm if the temperature remains constant?

If a gas occupies a volume of 10 L at 1 atm, what will be its volume at 2 atm if the temperature remains constant?

Step 1: Identify the initial conditions. The initial pressure (P1) is 1 atm and the initial volume (V1) is 10 L.
Step 2: Identify the final pressure (P2). The final pressure is 2 atm.
Step 3: Use Boyle's Law formula, which states that P1 * V1 = P2 * V2.
Step 4: Substitute the known values into the formula: 1 atm * 10 L = 2 atm * V2.
Step 5: Solve for V2. Rearrange the equation to find V2: V2 = (1 atm * 10 L) / (2 atm).
Step 6: Calculate V2: V2 = 10 L / 2 = 5 L.
Step 7: Conclude that if the pressure doubles, the volume halves, so the final volume is 5 L.

Boyle's Law – Boyle's Law states that for a given mass of gas at constant temperature, the pressure of the gas is inversely proportional to its volume.