A ball is thrown horizontally from the top of a cliff 45 m high. How far from th

Practice Questions

A ball is thrown horizontally from the top of a cliff 45 m high. How far from the base of the cliff will it land if it is thrown with a speed of 10 m/s?

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Questions & Step-by-Step Solutions

A ball is thrown horizontally from the top of a cliff 45 m high. How far from the base of the cliff will it land if it is thrown with a speed of 10 m/s?

Step 1: Identify the height of the cliff, which is 45 meters.
Step 2: Use the formula to calculate the time it takes for the ball to fall. The formula is time = sqrt(2 * height / g), where g is the acceleration due to gravity (approximately 9.8 m/s²).
Step 3: Plug in the values: time = sqrt(2 * 45 / 9.8).
Step 4: Calculate the value inside the square root: 2 * 45 = 90, then 90 / 9.8 ≈ 9.18.
Step 5: Take the square root of 9.18, which is approximately 3.03 seconds.
Step 6: Now, calculate the horizontal distance the ball travels using the formula: distance = speed * time.
Step 7: Plug in the values: distance = 10 m/s * 3.03 s.
Step 8: Calculate the distance: 10 * 3.03 = 30.3 meters.
Step 9: Round the distance to the nearest whole number, which is approximately 30 meters.

Projectile Motion – The question tests understanding of projectile motion, specifically the horizontal and vertical components of motion.
Kinematics – It involves using kinematic equations to determine the time of flight and horizontal distance traveled.
Free Fall – The vertical motion of the ball is influenced by gravity, requiring the use of the free fall equation.

A ball is thrown horizontally from the top of a cliff 45 m high. How far from th

Practice Questions

Questions & Step-by-Step Solutions

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