A ball is thrown horizontally from the top of a cliff 45 m high. How far from the base of the cliff will it land if it is thrown with a speed of 10 m/s?
Practice Questions
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Q1
A ball is thrown horizontally from the top of a cliff 45 m high. How far from the base of the cliff will it land if it is thrown with a speed of 10 m/s?
20 m
30 m
40 m
50 m
Time to fall = sqrt(2h/g) = sqrt(2*45/9.8) ≈ 3.03 s. Horizontal distance = speed * time = 10 * 3.03 ≈ 30.3 m, approximately 30 m.
Questions & Step-by-step Solutions
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Q
Q: A ball is thrown horizontally from the top of a cliff 45 m high. How far from the base of the cliff will it land if it is thrown with a speed of 10 m/s?
Solution: Time to fall = sqrt(2h/g) = sqrt(2*45/9.8) ≈ 3.03 s. Horizontal distance = speed * time = 10 * 3.03 ≈ 30.3 m, approximately 30 m.
Steps: 9
Step 1: Identify the height of the cliff, which is 45 meters.
Step 2: Use the formula to calculate the time it takes for the ball to fall. The formula is time = sqrt(2 * height / g), where g is the acceleration due to gravity (approximately 9.8 m/s²).
Step 3: Plug in the values: time = sqrt(2 * 45 / 9.8).
Step 4: Calculate the value inside the square root: 2 * 45 = 90, then 90 / 9.8 ≈ 9.18.
Step 5: Take the square root of 9.18, which is approximately 3.03 seconds.
Step 6: Now, calculate the horizontal distance the ball travels using the formula: distance = speed * time.
Step 7: Plug in the values: distance = 10 m/s * 3.03 s.
