An object is dropped from a height of 80 m. How long will it take to reach the ground?
Practice Questions
1 question
Q1
An object is dropped from a height of 80 m. How long will it take to reach the ground?
4 s
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Using the formula: h = 0.5 * g * t², where h = 80 m and g = 9.8 m/s². Solving for t gives t = sqrt(2h/g) = sqrt(2*80/9.8) ≈ 4.04 s, approximately 4 s.
Questions & Step-by-step Solutions
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Q
Q: An object is dropped from a height of 80 m. How long will it take to reach the ground?
Solution: Using the formula: h = 0.5 * g * t², where h = 80 m and g = 9.8 m/s². Solving for t gives t = sqrt(2h/g) = sqrt(2*80/9.8) ≈ 4.04 s, approximately 4 s.
Steps: 8
Step 1: Identify the height from which the object is dropped. In this case, the height (h) is 80 meters.
Step 2: Know the acceleration due to gravity (g), which is approximately 9.8 meters per second squared (m/s²).
Step 3: Use the formula for the height of a falling object: h = 0.5 * g * t².
Step 4: Rearrange the formula to solve for time (t): t = sqrt(2h/g).
Step 5: Substitute the values into the formula: t = sqrt(2 * 80 / 9.8).
Step 6: Calculate the value inside the square root: 2 * 80 = 160, then divide by 9.8 to get approximately 16.33.
Step 7: Take the square root of 16.33 to find t: t ≈ 4.04 seconds.
Step 8: Round the answer to the nearest whole number if needed. In this case, it is approximately 4 seconds.
