A projectile is thrown with a speed of 20 m/s at an angle of 45 degrees. What is

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Question: A projectile is thrown with a speed of 20 m/s at an angle of 45 degrees. What is the vertical component of the velocity?

Options:

Correct Answer: 14.14 m/s

Solution:

Vertical component (u_y) = u * sin(θ) = 20 * (√2/2) = 14.14 m/s.

A projectile is thrown with a speed of 20 m/s at an angle of 45 degrees. What is the vertical component of the velocity?

A projectile is thrown with a speed of 20 m/s at an angle of 45 degrees. What is the vertical component of the velocity?

Step 1: Identify the speed of the projectile, which is given as 20 m/s.
Step 2: Identify the angle at which the projectile is thrown, which is 45 degrees.
Step 3: Convert the angle from degrees to radians if necessary, but for 45 degrees, we can use the sine value directly.
Step 4: Find the sine of the angle. For 45 degrees, sin(45°) = √2/2.
Step 5: Use the formula for the vertical component of velocity: u_y = u * sin(θ).
Step 6: Substitute the values into the formula: u_y = 20 m/s * (√2/2).
Step 7: Calculate the vertical component: u_y = 20 * (√2/2) = 14.14 m/s.

Projectile Motion – Understanding the components of velocity in projectile motion, specifically how to calculate the vertical component using trigonometric functions.
Trigonometric Functions – Applying sine function to find the vertical component of velocity based on the launch angle.