A projectile is launched with a speed of 50 m/s at an angle of 30 degrees. What

A projectile is launched with a speed of 50 m/s at an angle of 30 degrees. What is the horizontal component of the velocity?

A projectile is launched with a speed of 50 m/s at an angle of 30 degrees. What is the horizontal component of the velocity?

Step 1: Identify the given values. The speed of the projectile (u) is 50 m/s and the angle (θ) is 30 degrees.
Step 2: Understand that the horizontal component of the velocity (u_x) can be found using the formula: u_x = u * cos(θ).
Step 3: Convert the angle from degrees to radians if necessary, but since we can use the cosine of 30 degrees directly, we can proceed.
Step 4: Find the cosine of 30 degrees. The cosine of 30 degrees is √3/2.
Step 5: Substitute the values into the formula: u_x = 50 * (√3/2).
Step 6: Calculate the horizontal component: u_x = 50 * 0.866 (approximately) = 43.3 m/s.

Projectile Motion – Understanding the components of velocity in projectile motion, specifically how to calculate the horizontal component using trigonometric functions.
Trigonometry in Physics – Applying cosine to find the horizontal component of velocity based on the launch angle.