An object is projected at an angle of 60 degrees with an initial velocity of 30 m/s. What is the time of flight?

1 question

1 item

Q: An object is projected at an angle of 60 degrees with an initial velocity of 30 m/s. What is the time of flight?

Solution: Time of flight (T) = (2u * sin(θ)) / g = (2 * 30 * √3/2) / 9.8 = 5.18 s.

Steps: 9

Step 1: Identify the given values. The initial velocity (u) is 30 m/s and the angle (θ) is 60 degrees.
Step 2: Convert the angle from degrees to radians if necessary, but here we can use the sine directly.
Step 3: Calculate the sine of the angle. sin(60 degrees) = √3/2.
Step 4: Use the formula for time of flight: T = (2u * sin(θ)) / g, where g is the acceleration due to gravity (approximately 9.8 m/s²).
Step 5: Substitute the values into the formula: T = (2 * 30 * √3/2) / 9.8.
Step 6: Simplify the equation: T = (30 * √3) / 9.8.
Step 7: Calculate the value of √3, which is approximately 1.732.
Step 8: Multiply 30 by 1.732 to get approximately 51.96.
Step 9: Divide 51.96 by 9.8 to find T: T ≈ 5.18 seconds.