An object is thrown horizontally from the top of a 45 m high cliff. How far from the base of the cliff will it land if it is thrown with a speed of 10 m/s?
Practice Questions
1 question
Q1
An object is thrown horizontally from the top of a 45 m high cliff. How far from the base of the cliff will it land if it is thrown with a speed of 10 m/s?
20 m
30 m
40 m
50 m
Time of flight (t) = √(2h/g) = √(2*45/9.8) = 3.03 s. Horizontal distance = speed * time = 10 * 3.03 = 30.3 m.
Questions & Step-by-step Solutions
1 item
Q
Q: An object is thrown horizontally from the top of a 45 m high cliff. How far from the base of the cliff will it land if it is thrown with a speed of 10 m/s?
Solution: Time of flight (t) = √(2h/g) = √(2*45/9.8) = 3.03 s. Horizontal distance = speed * time = 10 * 3.03 = 30.3 m.
Steps: 8
Step 1: Identify the height of the cliff, which is 45 meters.
Step 2: Use the formula to calculate the time of flight (t) for the object falling from the cliff. The formula is t = √(2h/g), where h is the height and g is the acceleration due to gravity (approximately 9.8 m/s²).
Step 3: Plug in the values into the formula: t = √(2 * 45 / 9.8).
Step 4: Calculate the value inside the square root: 2 * 45 = 90, then divide by 9.8 to get approximately 9.18.
Step 5: Take the square root of 9.18 to find the time of flight: t ≈ 3.03 seconds.
Step 6: Now, calculate the horizontal distance the object travels while it is in the air. Use the formula: distance = speed * time.
Step 7: Plug in the values: distance = 10 m/s * 3.03 s.
