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A charge of +5μC is placed in an electric field of strength 2000 N/C. What is th
A charge of +5μC is placed in an electric field of strength 2000 N/C. What is the force experienced by the charge?
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A charge of +5μC is placed in an electric field of strength 2000 N/C. What is the force experienced by the charge?
10N
1N
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Force F = qE = (5 × 10^-6 C) * (2000 N/C) = 10 N.
Questions & Step-by-step Solutions
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Q: A charge of +5μC is placed in an electric field of strength 2000 N/C. What is the force experienced by the charge?
Solution:
Force F = qE = (5 × 10^-6 C) * (2000 N/C) = 10 N.
Steps: 5
Show Steps
Step 1: Identify the charge value. The charge is +5μC, which is equal to 5 × 10^-6 C.
Step 2: Identify the electric field strength. The electric field strength is 2000 N/C.
Step 3: Use the formula for force in an electric field, which is F = qE, where F is the force, q is the charge, and E is the electric field strength.
Step 4: Substitute the values into the formula: F = (5 × 10^-6 C) * (2000 N/C).
Step 5: Calculate the force: F = 10 N.
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