What is the potential difference between two points in an electric field if the

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Question: What is the potential difference between two points in an electric field if the work done to move a charge of 2μC is 0.04 J?

Options:

Correct Answer: 40 V

Solution:

Potential difference V = W/q = 0.04 J / (2 × 10^-6 C) = 20,000 V = 20 V.

What is the potential difference between two points in an electric field if the work done to move a charge of 2μC is 0.04 J?

What is the potential difference between two points in an electric field if the work done to move a charge of 2μC is 0.04 J?

Step 1: Identify the formula for potential difference (V), which is V = W/q, where W is the work done and q is the charge.
Step 2: Note the values given in the question: Work done (W) = 0.04 J and Charge (q) = 2μC.
Step 3: Convert the charge from microcoulombs to coulombs: 2μC = 2 × 10^-6 C.
Step 4: Substitute the values into the formula: V = 0.04 J / (2 × 10^-6 C).
Step 5: Calculate the potential difference: V = 0.04 / 0.000002 = 20,000 V.
Step 6: Convert the result to volts: 20,000 V is the same as 20 kV.

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