What is the potential difference between two points in an electric field if the

What is the potential difference between two points in an electric field if the work done to move a charge of 2μC is 0.04 J?

What is the potential difference between two points in an electric field if the work done to move a charge of 2μC is 0.04 J?

Step 1: Identify the formula for potential difference (V), which is V = W/q, where W is the work done and q is the charge.
Step 2: Note the values given in the question: Work done (W) = 0.04 J and Charge (q) = 2μC.
Step 3: Convert the charge from microcoulombs to coulombs: 2μC = 2 × 10^-6 C.
Step 4: Substitute the values into the formula: V = 0.04 J / (2 × 10^-6 C).
Step 5: Calculate the potential difference: V = 0.04 / 0.000002 = 20,000 V.
Step 6: Convert the result to volts: 20,000 V is the same as 20 kV.

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