If two charges of +3μC and +5μC are placed 0.3m apart, what is the magnitude of

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Question: If two charges of +3μC and +5μC are placed 0.3m apart, what is the magnitude of the force between them?

Options:

Correct Answer: 0.45 N

Solution:

Using Coulomb\'s law, F = k * |q1 * q2| / r² = (9 × 10^9 N m²/C²) * |(3 × 10^-6 C) * (5 × 10^-6 C)| / (0.3 m)² = 0.45 N.

If two charges of +3μC and +5μC are placed 0.3m apart, what is the magnitude of the force between them?

If two charges of +3μC and +5μC are placed 0.3m apart, what is the magnitude of the force between them?

Step 1: Identify the charges. We have two charges: q1 = +3μC and q2 = +5μC.
Step 2: Convert the charges from microcoulombs (μC) to coulombs (C). 3μC = 3 × 10^-6 C and 5μC = 5 × 10^-6 C.
Step 3: Identify the distance between the charges. The distance r = 0.3 m.
Step 4: Use Coulomb's law formula: F = k * |q1 * q2| / r², where k = 9 × 10^9 N m²/C².
Step 5: Substitute the values into the formula: F = (9 × 10^9) * |(3 × 10^-6) * (5 × 10^-6)| / (0.3)².
Step 6: Calculate the product of the charges: (3 × 10^-6) * (5 × 10^-6) = 15 × 10^-12 C².
Step 7: Calculate the square of the distance: (0.3)² = 0.09 m².
Step 8: Substitute these values back into the formula: F = (9 × 10^9) * (15 × 10^-12) / 0.09.
Step 9: Calculate the force: F = (9 × 15 / 0.09) × 10^9 × 10^-12 = 0.45 N.

Coulomb's Law – Coulomb's law describes the electrostatic force between two charged objects, which is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them.