What is the electric field due to a point charge of +10μC at a distance of 0.2m?
Practice Questions
Q1
What is the electric field due to a point charge of +10μC at a distance of 0.2m?
22500 N/C
45000 N/C
50000 N/C
75000 N/C
Questions & Step-by-Step Solutions
What is the electric field due to a point charge of +10μC at a distance of 0.2m?
Step 1: Identify the values given in the problem. We have a point charge (q) of +10μC and a distance (r) of 0.2m.
Step 2: Convert the charge from microcoulombs to coulombs. +10μC = 10 × 10^-6 C.
Step 3: Use the formula for electric field (E) due to a point charge: E = k * |q| / r², where k is the electrostatic constant (approximately 9 × 10^9 N m²/C²).
Step 4: Substitute the values into the formula: E = (9 × 10^9 N m²/C²) * (10 × 10^-6 C) / (0.2 m)².
Step 5: Calculate the denominator: (0.2 m)² = 0.04 m².
Step 6: Now calculate the electric field: E = (9 × 10^9) * (10 × 10^-6) / 0.04.
Step 7: Perform the multiplication: (9 × 10^9) * (10 × 10^-6) = 90,000 N m²/C.
Step 8: Now divide by 0.04: 90,000 N m²/C / 0.04 = 2,250,000 N/C.
Step 9: Therefore, the electric field E = 225000 N/C.
