What is the electric potential energy of a charge of 1 C placed in an electric f

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Question: What is the electric potential energy of a charge of 1 C placed in an electric field of 10 N/C at a distance of 2 m?

Options:

Correct Answer: 20 J

Solution:

Electric potential energy U = q * V = q * E * d = 1 C * 10 N/C * 2 m = 20 J.

What is the electric potential energy of a charge of 1 C placed in an electric field of 10 N/C at a distance of 2 m?

What is the electric potential energy of a charge of 1 C placed in an electric field of 10 N/C at a distance of 2 m?

Step 1: Identify the charge (q). In this case, the charge is 1 Coulomb (C).
Step 2: Identify the electric field strength (E). Here, the electric field strength is 10 Newtons per Coulomb (N/C).
Step 3: Identify the distance (d) from the charge to the point in the electric field. The distance is 2 meters (m).
Step 4: Use the formula for electric potential energy (U), which is U = q * E * d.
Step 5: Substitute the values into the formula: U = 1 C * 10 N/C * 2 m.
Step 6: Calculate the result: U = 1 * 10 * 2 = 20 Joules (J).

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