A charge of -2μC is placed in an electric field of 500 N/C. What is the force acting on the charge?
Practice Questions
1 question
Q1
A charge of -2μC is placed in an electric field of 500 N/C. What is the force acting on the charge?
-1 N
1 N
-0.5 N
0.5 N
Force F = E * q = 500 N/C * -2 × 10^-6 C = -1 N.
Questions & Step-by-step Solutions
1 item
Q
Q: A charge of -2μC is placed in an electric field of 500 N/C. What is the force acting on the charge?
Solution: Force F = E * q = 500 N/C * -2 × 10^-6 C = -1 N.
Steps: 6
Step 1: Identify the values given in the problem. We have a charge (q) of -2 microcoulombs (μC) and an electric field (E) of 500 newtons per coulomb (N/C).
Step 2: Convert the charge from microcoulombs to coulombs. -2 μC is equal to -2 × 10^-6 C.
Step 3: Use the formula for force (F) in an electric field, which is F = E * q.
Step 4: Substitute the values into the formula: F = 500 N/C * -2 × 10^-6 C.
Step 5: Calculate the force: F = 500 * -2 × 10^-6 = -1 N.
Step 6: Interpret the result. The negative sign indicates that the force is in the opposite direction of the electric field.
