A charge of -2μC is placed in an electric field of 500 N/C. What is the force ac

Practice Questions

Q1
A charge of -2μC is placed in an electric field of 500 N/C. What is the force acting on the charge?
  1. -1 N
  2. 1 N
  3. -0.5 N
  4. 0.5 N

Questions & Step-by-Step Solutions

A charge of -2μC is placed in an electric field of 500 N/C. What is the force acting on the charge?
  • Step 1: Identify the values given in the problem. We have a charge (q) of -2 microcoulombs (μC) and an electric field (E) of 500 newtons per coulomb (N/C).
  • Step 2: Convert the charge from microcoulombs to coulombs. -2 μC is equal to -2 × 10^-6 C.
  • Step 3: Use the formula for force (F) in an electric field, which is F = E * q.
  • Step 4: Substitute the values into the formula: F = 500 N/C * -2 × 10^-6 C.
  • Step 5: Calculate the force: F = 500 * -2 × 10^-6 = -1 N.
  • Step 6: Interpret the result. The negative sign indicates that the force is in the opposite direction of the electric field.
  • Electric Force Calculation – The question tests the ability to calculate the force acting on a charge in an electric field using the formula F = E * q.
  • Understanding Charge Sign – It assesses the understanding of how the sign of the charge affects the direction of the force.
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