A charge of -2μC is placed in an electric field of 500 N/C. What is the force ac

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Question: A charge of -2μC is placed in an electric field of 500 N/C. What is the force acting on the charge?

Options:

Correct Answer: -1 N

Solution:

Force F = E * q = 500 N/C * -2 × 10^-6 C = -1 N.

A charge of -2μC is placed in an electric field of 500 N/C. What is the force acting on the charge?

A charge of -2μC is placed in an electric field of 500 N/C. What is the force acting on the charge?

Step 1: Identify the values given in the problem. We have a charge (q) of -2 microcoulombs (μC) and an electric field (E) of 500 newtons per coulomb (N/C).
Step 2: Convert the charge from microcoulombs to coulombs. -2 μC is equal to -2 × 10^-6 C.
Step 3: Use the formula for force (F) in an electric field, which is F = E * q.
Step 4: Substitute the values into the formula: F = 500 N/C * -2 × 10^-6 C.
Step 5: Calculate the force: F = 500 * -2 × 10^-6 = -1 N.
Step 6: Interpret the result. The negative sign indicates that the force is in the opposite direction of the electric field.

Electric Force Calculation – The question tests the ability to calculate the force acting on a charge in an electric field using the formula F = E * q.
Understanding Charge Sign – It assesses the understanding of how the sign of the charge affects the direction of the force.