A charge of +4μC is placed at the origin. What is the electric field at a point

A charge of +4μC is placed at the origin. What is the electric field at a point 2m away on the x-axis?

A charge of +4μC is placed at the origin. What is the electric field at a point 2m away on the x-axis?

Step 1: Identify the charge (q) and its value. Here, q = +4μC, which is equal to 4 × 10^-6 C.
Step 2: Identify the distance (r) from the charge to the point where we want to find the electric field. Here, r = 2m.
Step 3: Use the formula for electric field (E) due to a point charge: E = k * |q| / r^2, where k is the electrostatic constant (approximately 9 × 10^9 N m²/C²).
Step 4: Substitute the values into the formula: E = (9 × 10^9) * (4 × 10^-6) / (2)^2.
Step 5: Calculate the denominator: (2)^2 = 4.
Step 6: Now calculate the electric field: E = (9 × 10^9) * (4 × 10^-6) / 4.
Step 7: Simplify the calculation: E = (9 × 10^9 * 4 × 10^-6) / 4 = 9 × 10^9 * 10^-6 = 450 N/C.
Step 8: Conclude that the electric field at the point 2m away on the x-axis is 450 N/C.

Coulomb's Law – The electric field due to a point charge is calculated using Coulomb's Law, which states that the electric field (E) is proportional to the charge (q) and inversely proportional to the square of the distance (r) from the charge.
Electric Field Direction – Understanding that the electric field direction is away from positive charges and towards negative charges is crucial for interpreting the results.
Units of Measurement – Familiarity with the units of charge (Coulombs), distance (meters), and electric field (Newtons per Coulomb) is necessary for solving the problem correctly.