In a Wheatstone bridge, if the resistances are P = 5Ω, Q = 10Ω, R = 15Ω, what is

In a Wheatstone bridge, if the resistances are P = 5Ω, Q = 10Ω, R = 15Ω, what is the value of S for balance?

In a Wheatstone bridge, if the resistances are P = 5Ω, Q = 10Ω, R = 15Ω, what is the value of S for balance?

Step 1: Identify the resistances in the Wheatstone bridge. We have P = 5Ω, Q = 10Ω, and R = 15Ω.
Step 2: Write down the balance condition formula for the Wheatstone bridge, which is P/Q = R/S.
Step 3: Rearrange the formula to solve for S. This gives us S = (Q * R) / P.
Step 4: Substitute the values of Q, R, and P into the formula. So, S = (10 * 15) / 5.
Step 5: Calculate the multiplication first: 10 * 15 = 150.
Step 6: Now divide 150 by 5: 150 / 5 = 30.
Step 7: Therefore, the value of S for balance is 30Ω.

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