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In a circuit with two resistors in parallel, if one resistor is 6Ω and the other

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Question: In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing if the voltage across the circuit is 12V?

Options:

  1. 2A
  2. 4A
  3. 6A
  4. 8A

Correct Answer: 4A

Solution: 

Total resistance in parallel: 1/Rtotal = 1/6 + 1/3 = 1/2. Rtotal = 2Ω. Total current I = V/R = 12V/2Ω = 6A.

In a circuit with two resistors in parallel, if one resistor is 6Ω and the other

Practice Questions

Q1
In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing if the voltage across the circuit is 12V?
  1. 2A
  2. 4A
  3. 6A
  4. 8A

Questions & Step-by-Step Solutions

In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing if the voltage across the circuit is 12V?
  • Step 1: Identify the resistors in the circuit. We have one resistor of 6Ω and another of 3Ω.
  • Step 2: Use the formula for total resistance in parallel: 1/Rtotal = 1/R1 + 1/R2.
  • Step 3: Substitute the values into the formula: 1/Rtotal = 1/6 + 1/3.
  • Step 4: Find a common denominator to add the fractions. The common denominator for 6 and 3 is 6.
  • Step 5: Rewrite 1/3 as 2/6, so now we have: 1/Rtotal = 1/6 + 2/6.
  • Step 6: Add the fractions: 1/Rtotal = 3/6.
  • Step 7: Simplify the fraction: 1/Rtotal = 1/2.
  • Step 8: Invert the fraction to find Rtotal: Rtotal = 2Ω.
  • Step 9: Use Ohm's Law to find the total current: I = V/R.
  • Step 10: Substitute the values: I = 12V / 2Ω.
  • Step 11: Calculate the total current: I = 6A.
  • Parallel Resistors – Understanding how to calculate total resistance in a parallel circuit and applying Ohm's Law to find total current.
  • Ohm's Law – Using the relationship between voltage, current, and resistance to solve for current in a circuit.
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