In a circuit with a 10V battery and two resistors in series (R1 = 2Ω, R2 = 8Ω),

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Question: In a circuit with a 10V battery and two resistors in series (R1 = 2Ω, R2 = 8Ω), what is the current flowing through the circuit?

Options:

Correct Answer: 1A

Solution:

Total resistance R_total = R1 + R2 = 2Ω + 8Ω = 10Ω. Current I = V/R = 10V/10Ω = 1A.

In a circuit with a 10V battery and two resistors in series (R1 = 2Ω, R2 = 8Ω), what is the current flowing through the circuit?

In a circuit with a 10V battery and two resistors in series (R1 = 2Ω, R2 = 8Ω), what is the current flowing through the circuit?

Step 1: Identify the voltage of the battery, which is 10V.
Step 2: Identify the values of the resistors: R1 = 2Ω and R2 = 8Ω.
Step 3: Calculate the total resistance in the circuit by adding the resistances of R1 and R2: R_total = R1 + R2 = 2Ω + 8Ω.
Step 4: Perform the addition: R_total = 10Ω.
Step 5: Use Ohm's Law to find the current: I = V/R_total.
Step 6: Substitute the values into the formula: I = 10V / 10Ω.
Step 7: Perform the division to find the current: I = 1A.

Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = I * R.
Series Circuits – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.