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What is the total resistance of two resistors of 8Ω and 12Ω connected in series?

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Question: What is the total resistance of two resistors of 8Ω and 12Ω connected in series?

Options:

  1. 20Ω
  2. 24Ω
  3. 16Ω
  4. 18Ω

Correct Answer: 20Ω

Solution: 

In series, R_eq = R1 + R2 = 8 + 12 = 20Ω.

What is the total resistance of two resistors of 8Ω and 12Ω connected in series?

Practice Questions

Q1
What is the total resistance of two resistors of 8Ω and 12Ω connected in series?
  1. 20Ω
  2. 24Ω
  3. 16Ω
  4. 18Ω

Questions & Step-by-Step Solutions

What is the total resistance of two resistors of 8Ω and 12Ω connected in series?
  • Step 1: Identify the values of the resistors. We have R1 = 8Ω and R2 = 12Ω.
  • Step 2: Understand that when resistors are connected in series, the total resistance (R_eq) is the sum of the individual resistances.
  • Step 3: Write the formula for total resistance in series: R_eq = R1 + R2.
  • Step 4: Substitute the values into the formula: R_eq = 8Ω + 12Ω.
  • Step 5: Perform the addition: 8 + 12 = 20.
  • Step 6: Conclude that the total resistance is R_eq = 20Ω.
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